xn+1=xn+1⌊xn⌋x sub n plus 1 end-sub equals x sub n plus the fraction with numerator 1 and denominator the floor of x sub n end-floor end-fraction
. The beauty of the problem lies in proving that it doesn't "skip" over an integer due to the discrete steps. Why this matters Vietnamese problems frequently focus on: Selected Problems of the Vietnamese Mathematica...
The Vietnamese Mathematical Olympiad (VMO) is legendary in the competitive math world for its grueling multi-day format and its penchant for "beautifully difficult" geometry and functional equations. xn+1=xn+1⌊xn⌋x sub n plus 1 end-sub equals x
Deep dives into roots and coefficients that require more than just Vieta’s formulas. Deep dives into roots and coefficients that require
This problem is inspired by classic VMO analysis questions, which often bridge the gap between high school algebra and university-level calculus. Let a sequence be defined by
