using CodecZlib # Read a compressed file line by line stream = open("data.csv.gz") for line in eachline(GzipDecompressorStream(stream)) process(line) end Use code with caution. Copied to clipboard
using ZipFile r = ZipFile.Reader("your_file.zip") for f in r.files println("Filename: $(f.name)") # Read content as a string content = read(f, String) end close(r) Use code with caution. Copied to clipboard
If you are dealing with single compressed files (common in data science), you should use either CodecZlib.jl (recommended for most users) or GZip.jl. julia g.zip
a = [1, 2, 3] b = ["A", "B", "C"] # This creates an iterator of tuples: (1, "A"), (2, "B"), etc. zipped = zip(a, b) Use code with caution. Copied to clipboard Quick Reference Table Recommended Package Key Feature ZipFile.jl Standard archive reading/writing Streaming GZip CodecZlib.jl Robust, part of TranscodingStreams.jl Simple GZip Thin wrapper around C zlib functions
GitHub - JuliaIO/GZip.jl: A Julia interface for gzip functions in zlib using CodecZlib # Read a compressed file line
If you are working with Julia and need to handle .zip or .gz (gzip) files, there are several standard packages you can use depending on your specific needs. 1. Handling ZIP Archives
using ZipFile zdir = ZipFile.Writer("output.zip") # Add a file to the archive f = ZipFile.addfile(zdir, "hello.txt", method=ZipFile.Deflate) write(f, "Hello, world!") close(zdir) Use code with caution. Copied to clipboard 2. Handling GZip (.gz) Files a = [1, 2, 3] b = ["A",
You can use TranscodingStreams to read a file without fully decompressing it first. For zip files, you can try: * **ZipFile.jl** * The Julia Programming Language