The mathematical expression you provided follows the form of a product of fractions:
∏n=2kn65=(265)(365)(465)(565)(665)(765)(865)(965)…(k65)product from n equals 2 to k of n over 65 end-fraction equals open paren 2 over 65 end-fraction close paren open paren 3 over 65 end-fraction close paren open paren 4 over 65 end-fraction close paren open paren 5 over 65 end-fraction close paren open paren 6 over 65 end-fraction close paren open paren 7 over 65 end-fraction close paren open paren 8 over 65 end-fraction close paren open paren 9 over 65 end-fraction close paren … open paren k over 65 end-fraction close paren General Formula (2/65)(3/65)(4/65)(5/65)(6/65)(7/65)(8/65)(9/65...
This sequence can be expressed using factorials. For any given , the product is: The mathematical expression you provided follows the form
k!65k−1the fraction with numerator k exclamation mark and denominator 65 raised to the k minus 1 power end-fraction (Note: Since the sequence starts at , the denominator exponent is because there are terms in the product.) Calculated Values (2/65)(3/65)(4/65)(5/65)(6/65)(7/65)(8/65)(9/65...